An object moving in a straight line covers half of the distance with speed 5 m/s. The other half of the distance is covered in two equal time intervals with speed of 4 m/s and 6 m/s respectively. The average speed of object during the motion is.
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consider total distance as x.
then,
x/2 is travelled with speed 5m/s
time = (x/2) /5
x/4 is travelled with speed 4m/s
time = (x/4)/ 4
the other x/4 is travelled with speed 6m/s
time = (x/4)/6
total time taken
= (x/2) /5 + (x/4)/ 4 + (x/4)/6
= x/10 + x/16 + x/24
= 49x/240
average speed=
total distance/total time
= x/(49x/240)
= 240/49 m/s
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