Question

an object moving in r =100m circle satisfies : s = 36t-2t^3 , how much is the magnitude of accelration when t = 1s ? a = ____m/s^2​

Answer 1

s = 36t-2t³

We know,

Differentiation of displacement gives instantaneous velocity,

v = dx/dt = d36t-2t³/dt = 36-6t²

Differentiation of velocity gives instantaneous acceleration,

a = dv/dt = d36-6t²/dt = -12t

At t = 1s

a = 12m/s²or -12m/s²

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