Question

An object moving with 5 is uniformly accelerated at a rate of 2.5 −1
. What will be the velocity acquired by it after 10 seconds? How −2
much distance will it cover during this time?

Answer 1

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Answer 2

Answer:

u = 5m/s

a = 2.5m/s^2

t = 10 sec

v = ?

using first equation of Motion

v=u+at

v=5+(2.5×10)

v=5+25

v=30m/s

2)

u = 5m/s

a = 2.5m/s^2

t = 10 sec

v = 30m/s

s = ?

using 2nd equation of e

s=ut+1/2at^2

s=5×10+1/2×2.5×10×10

s=50+125

s=175m