Question

An object moving with a speed of 20m/s
If it is then accelarated with 6 m/s square , then
find the displacement covered by the
object in 5 seconds​

Answer 1

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Given :- }}}}$

• An object moving with a speed of 20m/s .
• It is accelerated with a velocity of 6m/s²

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ To Find:- }}}}$

• The displacement covered by the object at the end of 5 seconds .

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Solution :- }}}}$

Given that the initial Velocity of a object is 20m/s . And its accelerating with 6m/s² . We need to find the displacement covered at the end of 5 s . So here we can use the " Second equation of motion " , or the " Position time Relation " as ,

$\sf\dashrightarrow s = ut + \dfrac{1}{2}at^2$

Where ,

• s is Displacement
• u is Initial velocity
• t is time
• a is acclⁿ .

$\sf\dashrightarrow s = ( 20m/s * 5s) + \dfrac{1}{2} * 6m/s^2 * (5s)^2 \\\\\\\sf\dashrightarrow s = 100 m + 3m/s^2 * 25s^2 \\\\\\\sf\dashrightarrow s =100 m + 75m \\\\\\\sf\dashrightarrow \underset{\blue{\sf Required \ Displacement}}{\underbrace{\boxed{\pink{\frak{ Displacement(s) = 175 m }}}}}$

$\rule{200}4$

Answer 2



An object moving with a speed of 20m/s .

It is accelerated with a velocity of 6m/s²



The displacement covered by the object at the end of 5 seconds .



Given that the initial Velocity of a object is 20m/s . And its accelerating with 6m/s² . We need to find the displacement covered at the end of 5 s . So here we can use the " Second equation of motion " , or the " Position time Relation " as ,



Where ,

s is Displacement

u is Initial velocity

t is time

a is acclⁿ .