Question

an object moving with a velocity 5.6 m/s. on a surface comes to rest after traveling a distance of 16m then the coefficient of friction between the surface and object is
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Answer 1

Given:

u = 5.6 m/s

s = 16m

To find:

μ =?

Explanation:

The coefficient of friction between the surface and object is that the value that describes the ratio of the force of friction between two bodies and the force pressing them together.

We know that,

u = $\sqrt{2\mu gs}$

where

u = velocity of moving object

g = acceleration due to gravity

s = distance covered by the object

μ = coefficient of friction

Put the values in the above equation, we get

5.6 = $\sqrt{2\times\mu\times9.81\times16}$

squaring on both sides

31.36 = 313.92 μ

∴ μ = 0.09989

μ = 0.1

Answer 2

Explanation:

Given An object moving with a velocity 5.6 m/s. on a surface comes to rest after traveling a distance of 16 m then the coefficient of friction between the surface and object is

• So an object is moving with a velocity 5.6 m/s on a surface and it comes to rest after travelling a distance of 16m.
• We need to find the coefficient of friction.
• So the initial velocity is 5.6 m/s and rests after 16 m. So there is a friction and acts as the acceleration force on the body.
• So u = 5.6 m/s
• s = 16 m
• So we have ma = μmg
•             So a = μg
• So from equation of motion we have
•      V^2 – u^2 = 2aS
•      0 – (5.6)^2 = - 2 x μg x 16
•           - 31.36 = -32 x μ x 10
•             μ = 31.36 / 320
•       Or μ = 0.098 N

Reference link will be

https://brainly.in/question/260709