Math, asked by LittleStar011, 2 months ago

An object moving with a velocity of 30 m/s decelerate at the rate of 1.5 of m/s2. Find the time taken by the object to
come to rest​

Answers

Answered by ItzSweetPoison01
66

Answer:

We know that

V = u + at

0 = 30 + [-1.5 (t)]

0-30 = -1.5

-30 = -1.5t

-30/1.5 = t

30/1.5 = t

20 = t

Hence,

Time taken is 20 Seconds

Answered by VishalSharma01
143

Answer:

Step-by-step explanation:

Given,

Initial velocity, u = 30 m/s

Acceleration, a = - 1.5 m/s²

Final velocity, v = 0 m/s

To Find,

Time taken, t

Formula to be used.

1st equation of motion,

v = u + at

Solution,

Putting all the values, we get

v = u + at

⇒ 0 = 30 + (- 1.5) × t

⇒ 30 = 1.5t

⇒ 30/1.5 = t

⇒ 300/15 = t

20 = t

Hence, the time taken by the object to  come to rest​ is 20 seconds.

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