An object moving with a velocity of 30 m/s decelerate at the rate of 1.5 of m/s2. Find the time taken by the object to
come to rest
Answers
Answered by
66
Answer:
We know that
V = u + at
0 = 30 + [-1.5 (t)]
0-30 = -1.5
-30 = -1.5t
-30/1.5 = t
30/1.5 = t
20 = t
Hence,
Time taken is 20 Seconds
Answered by
143
Answer:
Step-by-step explanation:
Given,
Initial velocity, u = 30 m/s
Acceleration, a = - 1.5 m/s²
Final velocity, v = 0 m/s
To Find,
Time taken, t
Formula to be used.
1st equation of motion,
v = u + at
Solution,
Putting all the values, we get
v = u + at
⇒ 0 = 30 + (- 1.5) × t
⇒ 30 = 1.5t
⇒ 30/1.5 = t
⇒ 300/15 = t
⇒ 20 = t
Hence, the time taken by the object to come to rest is 20 seconds.
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