Question

An object moving with a velocity of 60m/s is brought to rest in 6 seconds
by a constant deceleration. Find the deceleration applied.

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

u=60m/s

v=0m/s

t=6s

a=v-u/t

a= -60/6

a= -10m/s2

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Answer 2

Answer:

10m/s^2

Step-by-step explanation:

it is given that initial velocity is 60 m/s and time taken to come at rest is 6sec by applying a=v-u/t a is 10