Question

An object moving with an initial velocity of 5.0 m/s is subjected to a uniform acceleration of -2.5 m/s. Find the displacement in the next 4.0 s.

Answer 1

Answer:-

S = 0m

Given :-

u = 5 m/s

a = -2.5 m/s²

t = 4s

To find :-

The displacement covered.

Displacement :- The shortest distance between initial and position of a body is known as displacement.

• It's SI unit is m.

• It is a vector quantity.

• The area under velocity time graph gives displacement.

Now, given acceleration is constant so we can freely use the equation of motion.

From 2nd equation of motion:-

★$S = ut + \dfrac{1}{2}at^2$

→$S = 5 \times 4 + \dfrac{1}{2}\times(-2.5)\times (4)^2$

→$S = 20 + \dfrac{}{}\times -2.5 \times 16$

→$S = 20 - 2.5 \times 8$

→$S = 0 m$

hence,

The displacement covered will be 0 m.

Answer 2

Answer:

Displacement (m) = 0m

Explanation:

Given Problem:

An object moving with an initial velocity of 5.0 m/s is subjected to a uniform acceleration of -2.5 m/s. Find the displacement in the next 4.0 s.

Solution:

To Find:

Covered Displacement.

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Method:

Given :-

$\bf = > u = 5 m/s\\\\\ = > a = -2.5 m/s^2\\\\\ = > t = 4s$

We know that,

$\bf {From\; 2^n^d\;equation\;of\;motion:}\\\\ \bigstar \bf {S = ut+\dfrac{1}{2}at^2}\bigstar\\\\\ S=5\times 4+\dfrac{1}{2}\times(-2.5)\times(4)^2\\\\\\ S = 20+\dfrac{1}{2}\times -2.5\times16\\\\\\ S = 20-2.5\times8\\\\\ S =0m\\\\\\\ Hence,It\;implies\;that\;the\;displacement\; is\;0m\\\\\\ Note:\\\\\\ Here,We\; use\;equation\;of\;motion.\;Because,The\;given\;acceleration\; is\; constant.\\ \ m = Displacement.$