An object, moving with constant acceleration and zero initial velocity, travels 48 m in 5.2s. What is the magnitude of its acceleration?
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PLZ MARK AS BRAINLIEST
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Answer:
Acceleration is 1.775m/s^2
Explanation:
Distance =48m
Time,t =5.2s
Intial velocity u =0
Final velocity,
v =distance/time = 48/5.2
= 9.23m/s
According to kinematic equations, v = u +at
a = (v- u )/t
= (9.23 - 0)/5.2
= 9.23/5.2
= 1.775m/s^2
Acceleration is 1.775m/s^2
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