an object moving with velocity 90 km/h undergoes a continuous constant retardation of 10m/s^2 . find the distance travelled by the object in 3rd second of its journey.
Answers
Answered by
0
s = ?
u = 90kmph = 90 ×5/18 = 25m/s
a = 10m/s^2
t = 3s
s = ut + 1/2at^2
s = 25 ×3 + 1/2 × 10 × 3^2
s = 75 + 45
s = 120m
Thanks
u = 90kmph = 90 ×5/18 = 25m/s
a = 10m/s^2
t = 3s
s = ut + 1/2at^2
s = 25 ×3 + 1/2 × 10 × 3^2
s = 75 + 45
s = 120m
Thanks
Similar questions