an object of 0.5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, it's nature and size.
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Radius of curvature, R = + 30 cm
Focal length, f = R/2 = + 30/2 cm = + 15 cm
Object-distance, u = – 20 cm
Height of object
h1′= 0.5 cm
Image-distance, v = ? Height of image h2′= ?
Focal length, f = R/2 = + 30/2 cm = + 15 cm
Object-distance, u = – 20 cm
Height of object
h1′= 0.5 cm
Image-distance, v = ? Height of image h2′= ?
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