an object of 10 kg is lift from the ground surface to the hieght of 5m calculate the work done•
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EASY TO ANSWER.
AS W.D = FORCE APPLIED * DISTANCE MOVED
F= MASS * ACCELERATION
F= 10 * 9.8 (GRAVITY)
F= 98 N
W.D= 98 *5 = 490 JOULES
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Answered by
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Answer:
490 Joules
Explanation:
Given,
m=10kg
h=5m
g=9.8m/s
Work done, W=mgh
W=10×9.8×5=490J
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