Question

An object of 10cm height is placed at a distance of 10cm from a convex mirror. The radius of curvature of the mirror is 30cm. Find the position, height and nature of its image.

Answer 1

$\mathtt{\huge{\underline{\red{Question\:?}}}}$

✴ An object of 10cm height is placed at a distance of 10cm from a convex mirror. The radius of curvature of the mirror is 30cm. Find the position, height and nature of its image.

$\mathtt{\huge{\underline{\green{Answer:-}}}}$

✏ The image formed at focus between the pole & focus .Its nature will be virtual , erect and diminished.Its size will be 6 cm .

$\mathcal{\huge{\underline{\pink{Solution:-}}}}$

Given :-

• An object of 10cm height is placed at a distance of 10cm from a convex mirror.

• The radius of curvature of the mirror is 30cm.

To Find :-

The position, height and nature of its image.

Solution :-

According to the question, we have a Convex mirror .

⭐ A convex mirror is a spherical reflecting mirror in which its bulging side faces the source of light.

We have,

• Focal Length (f) = R/2 = 30/2 = 15cm

• Initial distance (u) = -10cm

• Hieght (h) = 10 cm

Using mirror Formula,

1/f = 1/u + 1/v

=> 1/v = 1/f -1/u

=>1/v = 1/15+1/10

=> 1/v = 25/150

=> v = 6 cm

↗ The image formed at focus between the pole & focus .

Using formula of magnification ,

m = -(v/u) = (h'/h)

m = -(-6/10)

m = 3/5

↗ The nature of image will be virtual , erect and diminished.

Using mirror Formula for hieght

m = h'/h

=> 3/5 = h'/10

=> h' = 3×10/5

=> h' = 30/5

=> h' = 6

=> h' = 6cm

↗ The size of image will be 6 cm .

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