an object of 2 cm placed in 30 cm in front of a concave mirror should a sceen should be placed in order to obtain a sharp image? what is the nature and size of object
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Explanation:
u= -30
h= 2
F= -15
1/v+1/u=1/F
1/v=1/F-1/u
1/v=1/-15 -1/-30
1/v=1/-15+1/30
1/v=-15+30/-450
1/v=15/-450
v=-450/15
v=-30cm
m=h'/h=-v/u
h'/2=-(-30)/-30
h'/2=30/-30
-30h'=60
h'=60/-30
h'=-2cm
The image is real and inverted.The size of image is equal to the object size
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