Question

An object of 25 g mass is moving with 18 km/h and an additional force of 100 N is applied on the
object . Calculate the distance covered by the body in 5 minutes .

Answer 1

Given:-

• Mass of Object = 25g

• Initial Velocity = 18km/h = 5m/s

• Force Applied = 100N

• Time Taken = 5min = 300s.

To Find:-

• The Distance Covered bt Object in 5 minutes.

Formulae used:-

• F = ma

• S = ut + ½ × a × t²

Where,

• F = Force
• m = Mass
• a = Acceleration
• S = Distance
• u = Initial Velocity
• t = Time.

Now,

$\implies\sf{ F = ma }$

$\implies\sf{ 100 = 0.025 × a}$

$\implies\sf{ 100 = 0.025a}$

$\implies\sf{ \dfrac{100}{0.025} = a}$

$\implies\sf{ 4000= a}$

Thus, The Value of Acceleration is 4000m/s².

Now,

$\implies\rm{ S = ut + ½ × a × t²}$

$\implies\rm { S = 5 × 300 +½ × 4000 × (300)²}$

$\implies\rm{ S = 1500 + 2000 × 90000}$

$\implies\rm{ S = 1500 + 180000000}$

$\implies\rm{ s = 180015000m}$

$\implies\rm{ S = 180015km}$

So, The Distance Covered by object us 180015km.