an object of 2cm in size is placed 30cm in front of the concave mirror of focal length15cm. at what distance from the mirror should screen be placed in order to obtain a sharp image
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u= -30
h= 2
F= -15
1/v+1/u=1/F
1/v=1/F-1/u
1/v=1/-15 -1/-30
1/v=1/-15+1/30
1/v=-15+30/-450
1/v=15/-450
v=-450/15
v=-30cm
m=h'/h=-v/u
h'/2=-(-30)/-30
h'/2=30/-30
-30h'=60
h'=60/-30
h'=-2cm
The image is real and inverted.The size of image is equal to the object size
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