Question

An object of 2kg mass is dropped from 10 metres to ground. If the acceleration of the object is 9.8 m/s². Calculate the momentum of the object transferring to the ground?

Answer 1

Answer:

An object of 2kg mass is dropped from 10m to the ground. If the acceleration of the object is 9.8 m/s². The momentum of the object transferred to the ground is $28kgm/s$

Explanation:

When an object is dropped from a height $h$ its potential energy becomes equal to the kinetic energy at maximum height.

The gravitational potential energy is $PE=mgh$

and the kinetic energy $KE=\frac{1}{2}mv^{2}$

by equating these energies we get the velocity of the body $v=\sqrt{2gh}$

here, the mass of the object $m=2kg$

height to ground $h=10m$

and acceleration of the object $a=9.8m/s^{2}$

substitute the values to velocity equation, $v=\sqrt{2*9.8*10}=14m/s$

but the question is to find momentum transferred to the ground, that is equal to $P=mv$

hence momentum $P=2*14=28kgm/s$