an object of 3 cm high is placed at a distance of 8 cm from a concave mirror which produces a virtual image four centimetres high . what is the focal length of mirror
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Given:-
- Object height ,hi = 3cm
- Object distance , u= -8cm
- Image height ,ho = 4cm
To Calculate :-
- Focal length of mirror (f).
Solution:-
As we know that
Magnification ,m = hi/ho = -v/u
Substitute the value we get
→ 3/4 = -v/(-8)
→ 3/4 = v/8
→ v = 3×8/4
→ v = 24/4
→ v = 6 cm
Now using Mirror Formula
→ 1/v +1/u = 1/f
Substitute the value we get
→ 1/6 + 1(-8) = 1/f
→ 1/6 - 1/8 = 1/f
→ 4-3/24 = 1/f
→ 1/24 = 1/f
→ 1/f = 1/24
→ f = 24cm
∴. The Focal length of the mirror is 24cm.
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1
Answer:
24 cm
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