an object of 4 kg mass moving at 6 m/sec velaocity strikes a spring and compresses it by a distance x.if force constant of spring is 900n/m.what is value of x
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Given, mass of object m = 4Kg
velocity of object v = 6m/s
force constant of spring k = 900N/m
°•° object moves and strike a spring and compress it
So, kinetic energy of object is equal to the potential energy of spring
•°• 1/2 mv^2 = 1/2 kx^2
=> 4×6×6 = 900×kx^2
=> 144/900 = kx^2
=> x = √(144/900)
=> x = 12/30
=> x = 4/10
=> x = 0.4m
Hence, value of x is 0.4m
Given, mass of object m = 4Kg
velocity of object v = 6m/s
force constant of spring k = 900N/m
°•° object moves and strike a spring and compress it
So, kinetic energy of object is equal to the potential energy of spring
•°• 1/2 mv^2 = 1/2 kx^2
=> 4×6×6 = 900×kx^2
=> 144/900 = kx^2
=> x = √(144/900)
=> x = 12/30
=> x = 4/10
=> x = 0.4m
Hence, value of x is 0.4m
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