an object of 4cm height is placed at 60cm in front of concave mirror of focal length 20cm find the image distance and height of the image
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Answer:
Image distance is 30 cm and height of image is 2cm
Explanation:
Using ray optics concept and mirror formula...
We are given with f = focal length = -20cm,Object distance = u = -60cm.Using 1/v + 1/u = 1/f.......(1)
Here v is image distance from the mirror.
Substituting the values we get v = -30cm.
Negative sign implies that image formed is real and infront of the mirror.
Now using magnification m = -v/u = height of image/height of object.Substituting the vale we get height of image as -2 cm.
Here again negative sign implies that image formed is below the optical axis. Thankyou and follow me on brainly!!!!!!!!
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