An object of 5.0 cm in size is placed at a distance of 20.0 cm from a concave
mirror of focal length 15cm. At what distance from the mirror should a screen
be placed to obtain a sharp imge also calculate the size of image.
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Answers
Answered by
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Answer:hi sister idont know clearly about answer can you be as my friend
Answered by
1
Answer:
Given,
Object Size (I) = 5 cm
Object Distance (u) = 20 cm (negative)
Focal Length (f) = 15 cm (negative)
∴ 1/f = 1/v+1/u
= - 1/15 = 1/v+(-1/20)
= -1/15 = 1/v-1/20
= -1/15+1/20 = 1/v
= (-4+3)/60 = 1/v
= -1/60 = 1/v
= -60 cm = v
[Value is negative which states that image is real]
Linear Magnification (m) = -(v/u)
= -(-60/-20)
= -3
Image Size = 5*3 cm
= 15 cm
The Screen must be placed at 60 cm from the Mirror and the Image will have a size/height of 15 cm.
I hope this helps.
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