Physics, asked by lakshmiddarapureddy5, 10 months ago

an object of 5.0 cm is placed at a distance of 20.0 from a converging mirror of focal length 15. The celebrities at what distance from the screen replaced to get started with also calculate the size of image​

Answers

Answered by reachikjot93
1

Answer:

hi

Explanation:

Object distance = u = - 20cm

Focal length = f = - 15cm

We have to find the Place at which sharp image of object is made---> basically, we have to find image distance or 'v'

.'. By formula, 

-----> 1/f = 1/u + 1/v

===> 1/(-15) = 1/(-20) + 1/v

===> v = [ 20 * 15 ] / [ 15 - 20 ] = 300 / -5 = - 60cm

Hence, The screen needs to be placed at 60 cm before the Converging mirror... -->

Now, -v/u = image size / object size

.'. Image size = 60cm / 20cm * 5cm = 15cm

.'. The Image is going to be 15cm large.

Answered by BRAINLYARMY001
3

Answer:

hlo

your answer is here !

Explanation:

Heya user,

Object distance = u = - 20cm

Focal length = f = - 15cm

We have to find the Place at which sharp image of object is made---> basically, we have to find image distance or 'v'

.'. By formula, 

-----> 1/f = 1/u + 1/v

===> 1/(-15) = 1/(-20) + 1/v

===> v = [ 20 * 15 ] / [ 15 - 20 ] = 300 / -5 = - 60cm

Hence, The screen needs to be placed at 60 cm before the Converging mirror... --> [ to enjoy your movie in HD :-) Hehe ]

Now, -v/u = image size / object size

.'. Image size = 60cm / 20cm * 5cm = 15cm

.'. The Image is going to be 15cm large....... :-) [ Really Theatrical ]

follow \:  \:  \:  \: me

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