an object of 5 cm length is placed along the axis of a concave mirror of focal length 15 CM such that its near and is at 20 cm from the pole find the length of the image and magnification
Answers
Explanation:
ho=5cm
f= -15cm
u= -20cm
1/v + 1/u = 1/f
1/v = 1/-15 -1/20
= v = 8.57 cm
m= -v/u
m = 0.4285
m = hi/ho
hi = 2.1425
The length of the image and magnification are 37.50 cm and 7.5 respectively.
Explanation:
Given:
An object of 5 cm length is placed along the axis of a concave mirror of focal length 15 CM.
Its near and is at 20 cm from the pole.
To Find:
The length of the image and magnification.
Formula Used:
Mirror equation for concave mirror
----------- equation no.01.
Where,
u= Object distance
v= Image distance
f= Focal length of concave mirror.
Magnification equation
------------- equation no.02.
Where,
M= Magnification
I= Image length
O=Object length
Solution:
As given,an object of 5 cm length is placed along the axis of a concave mirror of focal length 15 CM.
I= 5 cm , f=-15 cm and u=-20 cm.
For end of the rod image distance =-20cm.
Applying the formula no.01.
For = -25 cm
Hence, Image length =
Applying the formula no.02.
Thus,the length of the image and magnification are 37.50 cm and 7.5 respectively.
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