Question

An object of 5 cm tall is placed before a concave mirror produces an image that 3cm from the mirror if the focal length of the mirror is 15cm determine the nature of the image and the magnification of the image

Answer 1

Explanation:

I dont know the answer of this question

Answer 2

The nature of image is virtual and upright. The magnification of image is -0.75

Explanation:

• Object size , u = -5 cm
• Focal length , f = -15 cm
• Image distance = 3 cm

v =?

Mirror formula:

1/v + 1/u = 1/f

1/v = 1/u - 1/f

1/v = -1/5 - (1/-15)

1/v = 1/5 + /15

1/v = -4/15

v = -15/4

v = -3.75

Magnification = - v / u

Magnification = 3.75 / -5

Magnification = - 0.75

The nature of image is virtual and upright.