Physics, asked by richapkb, 7 months ago

An object of 5 kg is far away from the surface of the earth and has an acceleration of 6 m/s² towards the center of earth. Find the force exerted by the object on the earth ​

Answers

Answered by bbhhbvjh
2

Answer:

f=ma

m=5kg

a=6m/s^{2}

Explanation:5*6=30N

Answered by DeenaMathew
1

The force exerted is 30 N by the object on the earth

Given:

An object of 5 kg is far away from the surface of the earth and has an acceleration of 6 m/s²

To Find:

The force exerted by the object on the earth ​

Solution:

According to Newton second law of motion,

Change rate of momentum is equal to force,

F= \frac{p2 - p1}{t}

where:

F is the force

p1 is the initial momentum

p2 is the final momentum

t is the time taken

As change rate of velocity is acceleration (a),

We have,

F = ma .................(1)

a is the acceleration of body,

when we solve any problems in physics we have to convert the units of quantity in a fixed system so I’ll use S.I. system to solve this problem,

m= 5.0 kg

a= 6.0 m/s2

Using (1),

F = ma

F = (5.0)(6.0)

F = 30.0 kg/s2

The force exerted is 30 N by the object on the earth

#SPJ2

Similar questions