an object of 5 kg mass is intially in rest sate after applying its velocity increases 40 metre par second how much force applied
Answers
Explanation:
Given, mass of the body, m=5kg;
Initial velocity of the body, u=0;
Force acting on the body, F=20N;
Time for which the force acts, t=10s
If a is the acceleration produced in the body,
a=
m
F
=
5
20
=4m/s
2
Let v be the velocity of the body after 10 s.
Clearly, v=u+at=0+(4)×(10)=40m/s
Kinetic energy acquired by the body,
E
k
=
2
1
mv
2
=
2
1
(5)×(40)
2
=4000J
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Answer:
ANSWER
Given, mass of the body, m=5kg;
Initial velocity of the body, u=0;
Force acting on the body, F=20N;
Time for which the force acts, t=10s
If a is the acceleration produced in the body,
a=
m
F
=
5
20
=4m/s
2
Let v be the velocity of the body after 10 s.
Clearly, v=u+at=0+(4)×(10)=40m/s
Kinetic energy acquired by the body,
E
k
=
2
1
mv
2
=
2
1
(5)×(40)
2
=4000J