Question

An object of 50 kg attains a speed of 10m/s in 5 seconds from zero velocity. Calculate force applied by engine.

Answer 1

Change in velocity= 10-0 =10 m/s
acceleration = change in velocity/time taken =10/5= 2 m/s^2
Force applied=mass*acceleration = 50* 2= 100 N

hope this helps!

Answer 2

$a = \frac{(v - u)}{t}$
$= \frac{10 -0 }{5}$
$= 2 \frac{m}{ {s}^{2} }$
$f = ma$
$= 50 \times 2$
$= 100 \: newton$
force applied by the engine = 100 N