Question

an object of 5cm high placed in a distance of 10cm from convex mirror at a radius of curvature 30cm . find the nature, position and size of the image .
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Answer 1

Answer:

Explanation:

O=5 cm

u=10 cm

f=30 cm

By using formula,

1/v + 1/u = 1/f

1/v + 1/10 = 1/30

1/v = 1/30 - 1/10

1/v = (1-3)/30

1/v = -2/30

1/v = - 1/15

v = 15 cm [(-) ve]

Thus,

The image is formed between focus and pole. The image is real, inverted.

Size

By using formula,

I/O = -v/u

I/5 = - (-15)/10

I/5 = 15/10

I = (5x15)/10

I = 75/10

I = 7.5 cm

Thus,

Image is magnified and is of the size 7.5 cm with respect to the object.