Question

An object of 5cm is placed at a distance of 15cm from a concave mirror of focal length 10cm, find position,nature and height of the image​

Answer 1

Answer:

height of object=5cm

u= -15 cm

focal length= -10 cm

1. position

1/f=1/v -1/u

1/-10=1/v -1/-15

-6 cm= v

m= v/u

m= -6/-15

m=0.4

1. nature:

virtual and erect

1. size of image:

m= height of image/ height of object

0.4= height of image/5

2cm= height of image.

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