An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 150 cm. find the position , size and nature of image.
Answers
Answer:
the position of image will be at focus and the size of image will be 5 cm and nature will be virtual image..
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Answer:
Height of object Ho = +5cm
Distance of object u= -10cm
Radius of curvature R= 150cm
Focal length f = 150/2= -75cm
Explanation:
FROM MIRROR FORMULA WE HAVE
I/V + 1/u = 1/f
1/v = -1/75 - (-1/10)
1/v = -1/75 + 1/10
1/v = + 13/150 cm
HENCE THE NATURE OF IMAGE IS VIRTUAL
The position of image is 13/150 = 0.086 cm in front of the mirror.
Now,
Height of object = +5cm
magnification, m = -v/u
= 13/150 / 10
m = 13/150* 1/10
m= 13/1500
Now, since m<1so the image formed is smaller than the object
m = hi /ho
m = hi/5
13/1500 *5 = hi
13/300 = hi
hi = 0.0433 cm
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