An object of 5kg is at rest on a smooth surface, if an external force acts on the object then what would be acceleration and velocity after 10 seconds of the object.
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Explanation:
ANSWER
Given,
mass=5kg
t
1
=2s
Initial velocity u=3m/s
Final velocity v=7m/s
t
2
=5s
So,
Let the Force be F
Let the acceleration be a
So,
a=
t
(v−u)
=
2
(7−3)
=2m/s
2
So the magnitude of the applied force is 10N
And the final velocity after 5s is v
So,
v=u+at
v=3+2×5
v=13m/s
The final velocity after 5s is 13m/s
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