Question

an object of 6 cm height is placed at a distance of 30 cm in front of a concave mirror of focal length 10cm at what distance from the mirror will be the image will be formed what are the characteristics of the image
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Answer 1

Answer:

Focal length(f) = 10 cm.

Object distance(u) = 15 cm.

Height of the Object = 6 cm.

Using the Mirror's formula,

1/f = 1/v + 1/u

⇒ 1/-10 = 1/v + 1/-15

⇒ 1/v = 1/-10 + 1/15

∴ 1/v = (-3 + 2)/30

⇒ v = -30 cm.

Since, image distance is negative, therefore, it is real and inverted.

Now, magnification = -v/u

= -(-30)/15

= 2

Since, magnification in greater than 1, therefore Image is magnified.

Also, m = H of image/H of object.

⇒ 2 = H of image/6

∴ Height of image = 12 cm.

Explanation:

Hope this helps U mate!!

Answer 2

Answer:

I hope, this answer help for you.