Question

an object of 6 cm height is placed at a distance of 30 cm in front of a concave mirror of focal length 10 cm . at what distance from the mirror , will the image be formed ? what are the characteristics of the image.

please solve it :)​

Answer 1

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■GIVEN THAT

▪︎focal length of a concave mirror(f)=10 cm

▪︎distance of the object (u)=15 cm

▪︎height of the object=6 cm

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■ By using mirror formula,

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{ - 10} = \frac{1}{v} + \frac{1}{ - 15}$

$\frac{1}{v} = \frac{1}{ - 10} + \frac{1}{ - 15}$

$\frac{1}{v} = \frac{ - 3 + 2}{30}$

$v = - 30$

▪︎Since image distance is negative therefore it is real and inverted

Now, magnification

$= \frac{ - v}{u}$

$= \frac{ - 30}{15} = - 2$

▪︎Now, since magnification is greater than 1 ,therefore image is magnified .

Also, m=H of image /H of object

           

$2 = \frac{h \: of \: image}{6}$

◆ Therefore, height of image =12 cm

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HOPE IT HELPS YOU!!!

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