Question

an object of 6 cm tall is placed 15 cm away from a concave mirror of focal length 10 cm find position,size and nature of image find the magnification of mirror​

Answer 1

Explanation:

We know that,

v

1

+

u

1

=

f

1

u = -15 cm

Focal length = -10 cm

∴

v

1

=

−10

1

−

(−15)

1

⇒

v

1

=

−10

1

+

15

1

=

30

−3+2

=−

30

1

⇒v=−30cm

Magnification (m)=

u

v

=

Object height

Image height

m=−

u

v

=+

−15

30

=−2

Also, Image height=−2×6=−12 cm

Therefore, a real, inverted and enlarged image of the object is formed beyond the centre of curvature.