Question

An object of 6cm In size is placed 50cm in front of the convex lens of focal length 30cm. At what distance from the lens should the lens be placed so that we could obtain a erect and diminished image. Draw a ray diagram to show that.
Please tell me the right answer ASAP

Answer 1

Explanation:

Height of object = +6 cm

Object distance = -50 cm

Focal length = +30 cm

Lens formula = 1/f = 1/v - 1/u

                        1/v = 1/f + 1/u

                        1/v = 1/30 - 1/50

                              = 5-3/150

                              = 2/150

                        Image distance = 150/2 = +75.5 cm

                           height of image  =  image distance

                            height of object       object distance

                              h =  75.5 x 6

                                         - 50

                                h = +9.06 cm

       Hence image formed is virtual, erect, and magnified

Answer 2

Answer:

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