Question

An object of 6cm is placed at 50cm in front of the convex lens of focal length 30 cm at what distance should the screen be placed in order to obtain a sharp image of the object find the nature and size of image .Also draw the ray diagram f

Answer 1

Answer:

given: height of object : 6cm

u : - 50 cm

f : +30cm

v : ?

1/f = 1/v - 1/u

1/30 = 1/v - 1/-50

1/v = 1/30 - 1/50 = 2/150 = 1/75

v = 75 cm

size of the image : m= v/u = 75/ -50=-3/2

hence, m = hieght of image / height of object = -3×6/2 = -9cm

nature of image real and inverted

diagram:

Answer 2

Answer:

Explanation:

given: height of object : 6cm

u : - 50 cm

f : +30cm

v : ?

1/f = 1/v - 1/u

1/30 = 1/v - 1/-50

1/v = 1/30 - 1/50 = 2/150 = 1/75

v = 75 cm

size of the image : m= v/u = 75/ -50=-3/2

hence, m = hieght of image / height of object = -3×6/2 = -9cm

nature of image real and inverted