Question

An object of a mass 10kg is raised from a height of 2m to 6m. What is the change in potential energy of the object?

Answer 1

Explanation:

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THE POTENTIAL ENERGY IS MEASURED BY THE FORMULA mgh

THE CHANGE IN POTENTIAL ENERGY IS MEASURED BY THE FORMULA       = mg(h2 - h1)

= 10*10*(6-2)

= 100*4

$= 400 \ kg*m^{2}/s^{2}$

PLEASE MAKE ME A BRAINLIST ANSWER FOR THE QUESTION.

Answer 2

Answer:

• Change in potential energy of the object is 392 J

Explanation:

Given

• Mass (m) = 10 Kg
• Height variation (h) = 2 m to 6 m
• Acceleration due to gravity (g) = 9.8 m/s²

To find

• Potential energy (P.E)

Solution

➝ Potential energy = m × g × h

• m = 10
• g = 9.8
• h = 6 m - 2 m
• h = 4 m

➝ Substituting we get :-

• 10 × 9.8 × 4
• 98 × 4
• 392

Hence, the change in potential energy of the object is 392 J.