Question

An object of certain mass is place at the earths surface. Then it is taken from the earths surface to a height h= 3R where R is the radius of the earth. Find in gravitational potential energy

Answer 1

Answer:

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Answer 2

The gravitational potential energy is $\dfrac{-GM_em}{ 4R_e}$ .

We need to find the potential energy at height $h=3R_e$ .

( where $R_e$ is the radius of the earth )

We know , potential energy is given as :

$U_h=\dfrac{-GM_em}{ R_e+h}$

Here , h is height from earths surface .

So , $h=3R_e$ .

Putting value of h in above equation we get :

$U_h=\dfrac{-GM_em}{ R_e+3R_e}\\\\\\U_h=\dfrac{-GM_em}{ 4R_e}$

Hence , this is the required solution .

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Gravitation

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