an object of from a cliff falls with a constant acceleration of 10 m/s^2 find its speed 2 second after it was dropped
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hey mate here is ur ans
we use the formula
Here we do +1/2at² as the body is falling under gravity
S=ut+1/at²
here u=0 (initially at rest)
so
S=1/2*a*t²=1/2*10*2²=5*4=20m
hope it helps you frnd
we use the formula
Here we do +1/2at² as the body is falling under gravity
S=ut+1/at²
here u=0 (initially at rest)
so
S=1/2*a*t²=1/2*10*2²=5*4=20m
hope it helps you frnd
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