an object of height 1.2 is placed before a concave mirror of focal lenght 20cm so the a real image is formed at a distance of 60cm from it find the pasition of an object what will be height of the image formed
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Hence the object distance is -30cm and height of object is 2.4cm
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Here,
Object height = 1.2cm
Focal length= -20cm
Image distance= -60cm
By mirror formula,
1\v+1/u=1/f
1/-60+1/u=1/-20
1/u=1/-20+1/60
1/u=3-1/-60
1/u=2/-60
u=-30
Therefore, object distance= 30cm
Now, magnification
Image height/object height=-v/u
Hi/1.2=-2
Image height=-2.4
Therefore image is real and inverted of 2.4cm
Object height = 1.2cm
Focal length= -20cm
Image distance= -60cm
By mirror formula,
1\v+1/u=1/f
1/-60+1/u=1/-20
1/u=1/-20+1/60
1/u=3-1/-60
1/u=2/-60
u=-30
Therefore, object distance= 30cm
Now, magnification
Image height/object height=-v/u
Hi/1.2=-2
Image height=-2.4
Therefore image is real and inverted of 2.4cm
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