an object of height 1.2 m height is placed before a concave mirror of focal length 20 cm at a distance of 60 cm from it .Find the position of object .and height of image?
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The position of the object is behind the centre of curvature
f=-20cm u=-60cm H=1.2m
mirror formula 1/v+1/u=1/f
-1/60+1/v=1/20
1/v=-1/20+1/60=-2/60=-1/30
v=-30
m=-v/u=h/H
=30/-60=-1/2=h/1.2
h=-0.6
height of image is equal to 0.6 m
f=-20cm u=-60cm H=1.2m
mirror formula 1/v+1/u=1/f
-1/60+1/v=1/20
1/v=-1/20+1/60=-2/60=-1/30
v=-30
m=-v/u=h/H
=30/-60=-1/2=h/1.2
h=-0.6
height of image is equal to 0.6 m
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