an object of height 1.2 m is a placed before a concave mirror of focal length20 cm so that a real image is formed at a distance of 60 cm from it find the position of an object what will be the height of the image formed
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Given: height of object = 1.2m
f = -20cm
v = -60cm
1/f = 1/v+1/u
1/-20 = 1/-60+1/u
1/u = -1/30
u = -30cm
-v/u = hi/ho
+60/-30 = hi/120
hi = -240cm
f = -20cm
v = -60cm
1/f = 1/v+1/u
1/-20 = 1/-60+1/u
1/u = -1/30
u = -30cm
-v/u = hi/ho
+60/-30 = hi/120
hi = -240cm
Answered by
1
Given
Concave Mirror
Focal Length (f) = -20cm
Image Distance (v) = -60cm
Object Distance (u) = u
Mirror Formula => 1/f = 1/u + 1/v
=> 1/u = 1/f - 1/v
=> 1/u = 1/-20 - 1/-60
=> 1/u = 1/60 - 1/20
=> 1/u = (1 - 3)/60
=> 1/u = -2/60
=> u = -30cm
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