an object of height 1.2 M is placed before a concave mirror of focal length 20cm so that a real image is formed at a distance of 60 cm from it find the position of an object what will be the height of the image formed
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V= -60 cm
F= -20cm
H= 1.2cm = 120cm
1/v + 1/u = 1/f
1/-60 + 1/u = 1/-20
1/u = 1/-20 - 1/-60
1/u = 1/-20 + 1/60
1/u = (-3 + 1)/60
1/u =-2/60
u = -30 cm
- (v/u) = h*/h
-(-60/-30) = h*/h
-2 = h*/120
h* = -240cm
F= -20cm
H= 1.2cm = 120cm
1/v + 1/u = 1/f
1/-60 + 1/u = 1/-20
1/u = 1/-20 - 1/-60
1/u = 1/-20 + 1/60
1/u = (-3 + 1)/60
1/u =-2/60
u = -30 cm
- (v/u) = h*/h
-(-60/-30) = h*/h
-2 = h*/120
h* = -240cm
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