Question

An object of height 1.2m is placed before a concave mirror of focal length 20cm so that a real image is formed at a distance of 60cm from it. Find the position of an object. What will be the height of the image formed?

Answer 1

Given,
ho = 1.2m =120cm
f = - 20cm (since concave mirror)
v = - 60cm (since real images are formed in lhs of mirror)

Now,
1/f = 1/v + 1/u
1/-20 = 1/ - 60 + 1/u
1/u = - 1/20 + 1/60
1/u = - 2/60
u = - 30 cm. (position of the object)
now hi :-
hi/ho = -v/u
hi = - (-60 × 120) ÷ -30 = - 240 m = 2.4 cm

Answer 2

Answer:

u = 30 cm

$\display \text{h _i = 2.4 cm}$

Explanation:

We have given :

Focal length = 20 cm

Image distance =  60 cm

We have to find object distance .

We know :

1 / f = 1 / v + 1 / u

Since image formed is real :

f = - 20 cm and v = - 60 cm

1 / u = 1 - 3 / 60

u = - 30 cm

Hence object distance is 30 cm .

Also given object height = 1.2 cm

We know :

h_i / h_o = - v / u

h_i / 1.2 = - 60 / 20

h_i = - 2.4 cm

Hence image height is 2.4 cm .