Question

An object of height 1.2m is placed before a concave mirror of focal length 20 cm so that a real image is formed at a distance of 60cm from it find the position of an object and what will be the height of the image formed

Answer 1

by the equation 1/v+1/u=1/f
u =vf/v-f
now as its a concave mirror hence the
v = - ve
f= - ve
hence u=(-60×-20)/-60-(-20) = -30 cm
now m= - (v/u)= -(-60/-30) = -2
now here the negative sign just tells the image's inversion
now final height if object will be magnified by 2 times hence funal image height will be of 1.2× 2 = 2.4 mtrs
thanks buddy plzz help the other learners
sikshit bharat Ujjwal bharat !!
jai hind

Answer 2

Answer:

u = 30 cm

$\display \text{h _i = 2.4 cm}$

Explanation:

We have given :

Focal length = 20 cm

Image distance =  60 cm

We have to find object distance .

We know :

1 / f = 1 / v + 1 / u

Since image formed is real :

f = - 20 cm and v = - 60 cm

1 / u = 1 - 3 / 60

u = - 30 cm

Hence object distance is 30 cm .

Also given object height = 1.2 cm

We know :

h_i / h_o = - v / u

h_i / 1.2 = - 60 / 20

h_i = - 2.4 cm

Hence image height is 2.4 cm .