Question

An object of height 1.5 m is placed at a distance of 15 cm from a concave mirror of focal length 30 cm so that a virtual image is formed. Calculate position, nature and size of the image. Draw a ray diagram to show the image formation in the above case​

Answer 1

Explanation:

Correct option is

A

−10 cm

Given,

object height h1=1.5 cm

real image length h2=−3cm

Position of object from the mirror u=−15cm

Mirror magnification formula

m=h1h2=−uv

1.5−3=−15−v

v=−30cm

Apply Mirror formula

f1=−301+−151

f=−10cm 

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