AN OBJECT OF HEIGHT 10 CM IS KEPT AT A DISTANCE OF 150 CM IN FRONT OF CONCAVE MIRRORHAVING RADIUS OF CURVATURE 2M. WHAT IS NATURE, HEIGHT AND DISTANCE OF IMAGE FROM MIRROR?
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Answer:
Object distance u=−10 cm
Radius of curvature of concave mirror R=−15 cm
Thus its focal length f=
2
R
=−
2
15
cm
Using mirror formula :
v
1
+
u
1
=
f
1
∴
v
1
+
−10
1
=−
15
2
⟹ v=−30 cm
Magnification m=
u
−v
∴ m=
−10
−(−30)
=−3
Negative sign indicates that the image formed is inverted in nature.
Magnitude of magnification is greater than 1 which indicates that magnified image is formed.
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