An object of height 10cm is kept a Jot a distance of 36 cm from a concave mirror of focal length 12cm. Find the position , nature and height of the image formed. Also draw a ray diagram to show the formation of image.
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Answers
[ Refer the attachment for figure ]
Given that, image distance (u) from the mirror is -36 cm, height of object (h) is 10 cm and focal length (f) of concave mirror is -12 cm.
We have to find the position, nature and height of the image formed.
Using the Mirror formula:
1/f = 1/v + 1/u
Substitute the values,
→ 1/(-12) = 1/v + 1/(-36)
→ 1/v = -1/12 + 1/36
→ 1/v = (-3 + 1)/36
→ 1/v = -2/36
→ v = -18
Therefore, the image distance from the mirror is 18 cm.
Also, using Magnification formula:
m = -v/u
Substitute the values,
→ m = -(-18)/(-36)
→ m = - 0.5
Also, m = h'/h
→ -0.5 = h'/10
→ -5 = h'
Therefore, the height of the image is 5 cm.
Nature of the image: The image formed is real, inverted and smaller in size.
Explanation:
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