Science, asked by divya1963, 8 months ago

An object of height 10cm is kept a Jot a distance of 36 cm from a concave mirror of focal length 12cm. Find the position , nature and height of the image formed. Also draw a ray diagram to show the formation of image.
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Answers

Answered by Anonymous
21

[ Refer the attachment for figure ]

Given that, image distance (u) from the mirror is -36 cm, height of object (h) is 10 cm and focal length (f) of concave mirror is -12 cm.

We have to find the position, nature and height of the image formed.

Using the Mirror formula:

1/f = 1/v + 1/u

Substitute the values,

→ 1/(-12) = 1/v + 1/(-36)

→ 1/v = -1/12 + 1/36

→ 1/v = (-3 + 1)/36

→ 1/v = -2/36

→ v = -18

Therefore, the image distance from the mirror is 18 cm.

Also, using Magnification formula:

m = -v/u

Substitute the values,

→ m = -(-18)/(-36)

→ m = - 0.5

Also, m = h'/h

→ -0.5 = h'/10

→ -5 = h'

Therefore, the height of the image is 5 cm.

Nature of the image: The image formed is real, inverted and smaller in size.

Attachments:
Answered by nandinisaxena70
0

Explanation:

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