an object of height 2.4 cm is placed before a concave mirror of focal length 25 CM so that image is formed at a distance of 75 cm find the position of an object what will be the height of the image formed
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Answer:
ho - 2.4 cm
f = -25 cm
v = -75 cm
u = ?
hi = ?
1/f = 1/v + 1/u ( mirror formula)
1/u = 1/f - 1/v
= 1/75 - 1/25
= 25-75/ 25x75
= -50/ 1875
= -1/37.5
u = -37.5 cm
m = hi/ho = v/u
= hi/2.4 = -75/-37.5
= hi = -75x2.4/-37.5
= hi = 4.8 cm
Therefore, the height of the image formed is 4.8 cm.
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