Question

An object of height 2 cm is held at a distance of 40 cm in front of a concave mirror of focal length
15 cm? Find the nature, position and size of the image?

pls faltu ke añswer nhi ​

Answer 1

Answer:

$\huge{\underline{\underline{\mathbb{\blue{Given:-}}}}}$

Focal length, f = 15 cm

object distance, 4 = 25 cm

object height, ho= 40 cm

From mirror formula

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{ - 5} = \frac{1}{ - 25} + \frac{1}{v}$

$= > \frac{1}{v} = \frac{1}{ - 15} + \frac{1}{25}$

$v = 37.5cm$

$magnification \: \: m = \frac{v}{u} = \frac{hi}{ho}$

$= > m = - \frac{( - 37.5)}{ - 25} \frac{hi}{4}$

$hi = \frac{ - 37.5 \times 4}{25}$

$hi = 6cm$

Hope it's help you.....